plotting matrices with image in 2D

[SalahEddineGhamri]

Currently, I am trying to plot an obstacle map using image function. I am not sure how to use the dimensions optional to rotate the matrix.

The following code is used:

let original_matrix = DMatrix::<i32>::from_row_slice(10, 14, &[
        0, 0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0,
        0, 0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0,
        0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0,
        0, 0, 0, 0, 1, 0, 0, 0, 0 ,0 ,0 ,0, 0, 0,
        0, 0, 0, 0, 1, 0, 0, 0, 0 ,0 ,0 ,0, 0, 0,
        0, 0, 0, 0, 0, 0, 0, 0, 1 ,0 ,0 ,0, 0, 0,
        0, 0, 0, 0, 0, 0, 0, 0, 1 ,0 ,0 ,0, 0, 0,
        0, 0, 0, 0, 0, 0, 0, 0, 1 ,0 ,0 ,0, 0, 0,
        0, 0, 0, 0, 0, 0, 0, 0, 1 ,0 ,0 ,0, 0, 0,
        0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0
    ]);

    let obstacle_map = grid_map::Map::new(original_matrix, 3).unwrap();

    let flattened_map: Vec<_> = obstacle_map.transpose().iter().cloned().collect();

    let (height, width) = obstacle_map.shape();

    let dimensions = Some((0.0, 0.0, ((width - 1) as f64), -((height - 1) as f64 )));

    fg.clear_axes();

    fg.axes2d().image(flattened_map.clone(), height, width, dimensions, &[]);

the x axis is the column direction and the y axis is the rows direction. How ever the resultant image is the following (I am plotting two other points in the chart):

maybe, I am missing something, but I thought dimensions will rotate image to look as the numerical view of it.

I wan the image to look like this with same axis of the image above:
0, 0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 1, 0, 0, 0, 0 ,0 ,0 ,0, 0, 0,
0, 0, 0, 0, 1, 0, 0, 0, 0 ,0 ,0 ,0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 1 ,0 ,0 ,0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 1 ,0 ,0 ,0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 1 ,0 ,0 ,0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 1 ,0 ,0 ,0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0