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Transfer the δ halo exponents 11, 24, 26, 26, 6 across cells; robust to the 'rounded' reading (no new κ) - #4462
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Mister-Meeseeks merged 2 commits intoOct 22, 2026
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…to the 'rounded' reading (no new κ) Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>
Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>
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Summary
This adds
research/delta-cross-cell-transfer/. It answers the open question of #4452 (and of my #4460): do jwr404's within-cell δ exponents 11, 24, 26, 26 and 6 survive on the banded reference across cells?Claim type: a conditional transfer lemma plus a robustness lemma, with exact rational checks. No new κ. The ideal gaps
1/(8p²)stay hypotheses.Results
0 ≤ H ≤ n). This is Apply the smaller halo exponents across a cell, under the downward reading (no new κ) #4442's column split with δ in place of1/(16p²). It givesoff(H) ≤ T_in/(1−δ) + T_out ≤ (1−g)/(1−δ). The global inverse ceiling is therefore exactly Lower the within-cell halo exponents to 11, 24, 26, 26 and 6 (no new κ) #4452'sU, and all five exponents transfer verbatim.ρ ≤ 1/(32p³)per row or column). We get‖H^{−1}‖₂ < 10p², so 11, 24, 26, 26 and 6 all hold. Per entry, an absolute error up to1/(64p⁴)in either direction suffices.16p²−1, a 1/64 overshoot brokep = 2, so the downward-vs-"rounded" (FINE-PRIME) wording mattered. Under δ it no longer matters for these exponents. FINE-PRIME'spoly(p)2^{−(C−o(1))p}perturbation works eventually.p = 2the excess tolerance on this route lies in(0.0091, 0.0092).Evidence
The checks are exact for each
pfrom 2 to 64, plus all-pinequalities. The split identity is proved as a polynomial identity on a 3×3×3 grid. The LOG-A, FINE-PRIME and downstream phrases are pinned. Head:c8fd7f81696d5b8b838c996cc384e76ab378dae3. Base: canonical main2a13eb18.Not covered
Credit: James Reed (jwr404: #4442, #4451, #4452) and mihir-s-05 (#4449). Prepared by Ryanson Jonathan with substantial Claude Code (Claude Opus 5.5) assistance.
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