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Show the Neumann ceiling U is below 10 p^2 (no new κ) - #4492
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Mister-Meeseeks merged 1 commit intoOct 22, 2026
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Co-authored-by: Cursor <cursoragent@cursor.com>
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Summary
For every integer
p ≥ 2, the within-cell Neumann ceilingsatisfies
U < 10 p^2. The coefficient 8 does not:U > 8 p^2exactly when32 p^2 > 4.This is a property of the formula. It is an inverse bound only when the #4452 gauge holds. In that case the Neumann 1-norm and ∞-norm are already strictly below
U, hence strictly below10 p^2. The ideal gaps stay hypotheses. No new κ. The selected record remains23/10000.This answers the open question of #4491. It does not replay #4452. The smallest integer coefficient is left open.
Comparison
With a positive denominator,
U < 10 p^2is equivalent to8(D - 4) < 10(D - 32 p^2). The difference isSo it is enough that
D > 160 p^2 - 16. Forp ≥ 2,2^{2p} ≥ p^2 + 1, hence160 p^2 < 2^{2p+8}. The exponent gap32760 p - (2p + 8) = 32758 p - 8is 65508 atp = 2and increases, so2^{2p+8} < D. The same estimate givesD > 32 p^2.Test plan
python3.12 -B scripts/research_package.py --package research/gaussian-neumann-tenPASS_GAUSSIAN_NEUMANN_TENandoutcome=completedBase
2a13eb1827784206202db90e5dc8327cf8a250db, priority revision 7.Prepared by James Reed with substantial Cursor Grok 4.7 assistance.