Exercises 1.1.2 what happens if I remove from the psvm:

a. public
    Still compiles get "error: can't find main(String[]) method in class: Chapter1a" when trying to run

b. static
    same, can't find main

c. void
    compile error, "Chapter1a.java:2: error: invalid method declaration; return type required
    public static main(String[] args) {"

d. args
    compile error, "Chapter1a.java:2: error: <identifier> expected
    public static void main(String[] ) {"

1.1.3 what happens if you misspell i.e. omit second letter in:

a. public
    Chapter1a.java:2: error: <identifier> expected
    pblic static void main(String[] args) {

b. static
    Chapter1a.java:2: error: <identifier> expected
    public satic void main(String[] args) {

c. void
    Chapter1a.java:2: error: cannot find symbol
    public static vid main(String[] args) {
    ^
    symbol:   class vid
    location: class Chapter1a
d. args
    nothing really, you can still implement the "ags" if you wanted, but int his case it doesn't do anything because we're not using the "ags" array

1.1.4 what happens if you add lines as white space inside a string literal? unclosed string literal error, which is interesting because in a lot of cases white space doesn't do anything special

1.1.5 With the UserArgument class what happens when you enter

a. java UserArgument java
    just uses "java" as the arg string
b. java UserArgument @!&^%
    gives errors for the @ and &
c.  java UserArgument.java Bob
    runs fine, uses Bob as arg
d. java UserArgument.java Alice Bob
    runs fine, we only call the first arg in the array which is Alice

1.1.6 Write program that can take in three args and print them out modified UserArgument to take in arbitrary number of arguments and print a hello string for each argument

1.2.1 int t = a; b = t; a = b; sets the value of t to the value of a, then the value of b to the value of t, then a to the value of b, in this case the last expression does nothing because the values are the same at this point

1.2.2 trig identity program including in Chapter1 class floating point rounding errors account for the slight mismatches

1.2.3 boolean logic output of (!(a && b) && (a || b) || ((a && b) || !(a || b))) !(a && b) && (a || b) will always evaluate to !(a && b)